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Equation of the normal at a point on the parabola

y2=36x , whose ordinate is three times its abcissac
is-

a
2x+3y+44=0
b
2x−3y+44=0
c
2x+3y−44=0
d
2x−3y=0

detailed solution

Correct option is C

Equation of the normal at 9m2,−18m on theparabola is y=mx−2×9m−9m3  where  −18m=3×9m2. i.e., m=0 or m=−2/3. For m=−2/3,  the equationof the normal is 2x+3y−44=0.

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