First slide

Equation of line in Straight lines

Question

The equation of one of the sides of an isosceles right angled triangle whose hypotenuse is given by 3x+4y=4 and the opposite vertex of the hypotenuse is (2,2) is

Moderate

A

7x-y=16
B

7x+y=16
C

x+7y=16
D

x-7y+16=0

Solution

$\Rightarrow \frac{7 m}{4} = \frac{1}{4} \Rightarrow m = \frac{1}{7}$ and m = -7
$\Rightarrow \frac{7 m}{4} = \frac{1}{4} \Rightarrow m = \frac{1}{7}$
Equation of sides $\Rightarrow x - 7 y + 12 = 0$ and $7 x + y - 16 = 0$

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