The equation of one of the sides of an isosceles right angled triangle whose hypotenuse is given by 3x+4y=4 and the opposite vertex of the hypotenuse is (2,2) is
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a
7x-y=16
b
7x+y=16
c
x+7y=16
d
x-7y+16=0
answer is B.
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Detailed Solution
⇒7m4=14⇒m=17 and m = -7⇒7m4=14⇒m=17Equation of sides ⇒x−7y+12=0 and 7x+y−16=0