The equation of one of the sides of an isosceles right angled triangle whose hypotenuse is given by 3x+4y=4 and the opposite vertex of the hypotenuse is (2,2) is

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7x-y=16

7x+y=16

x+7y=16

x-7y+16=0

answer is B.

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Detailed Solution

⇒7m4=14⇒m=17 and m = -7⇒7m4=14⇒m=17Equation of sides ⇒x−7y+12=0 and 7x+y−16=0

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