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Q.

The equation of one of the straight lines which passes through the point (1,3) and makes  an angle tan-12 with the straight line, y+1=32x is:

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a

42x+5y−(15+42)=0

b

52x+4y−(15+42)=0

c

42x−5y−(5+42)=0

d

an angle tan-1(2) with the straight line, y+1=32x is:

answer is A.

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Detailed Solution

y−3=tanθ±αx−1=tanθ±tanα1∓tanθtanαx−1=32±21∓6x−1y−3=42−5x−1  or y−3=227x−1−5y+15=42x−42
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