Equation of the perpendicular line from (3, –1, 11) to the line x2=y−23=z−34 is

Let P be the foot of the perpendicular from A (3, –1, 11) to the given line then P = (2r , 3r + 2, 4r + 3)D.r’s of A.P are (2r – 3, 3r + 3, 4r – 8)AP↔ is perpendicular to the given line⇒ 2(2r – 3) + 3(3r + 3) + 4(4r – 8)=0 ⇒ r = 1   P = (2, 5, 7)D.r’s of   AP↔ are (1, –6, 4)