The equation of the plane containing the line x−x1l=y−y1m=z−z2n is a(x−x1)+b(y−y1)+c(z−z1)=0 where
ax1+by1+cz1=0
al+bm+cn=0
al=bm=cn
lx1+my1+nz1=0
Plane contains the given line normal to the plane must be perpendicular to the line so, al + bm + cn = 0.