The equation of the plane containing the line x−x1l=y−y1m=z−z2n is a(x−x1)+b(y−y1)+c(z−z1)=0 where

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ax1+by1+cz1=0

al+bm+cn=0

al=bm=cn

lx1+my1+nz1=0

answer is B.

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Detailed Solution

Plane contains the given line normal to the plane must be perpendicular to the line so, al + bm + cn = 0.

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