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Questions  

The equation of the plane containing the line xx1l=yy1m=zz2n is a(xx1)+b(yy1)+c(zz1)=0 where

a
ax1+by1+cz1=0
b
al+bm+cn=0
c
al=bm=cn
d
lx1+my1+nz1=0

detailed solution

Correct option is B

Plane contains the given line normal to the plane must be perpendicular to the line so, al + bm + cn = 0.

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