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Questions  

An equation of the plane passing through the line of intersection of the planes x+y+z=6and 2x+3y+4z+5=0 and passing through (1, 1, 1) is 

a
2x+3y+4z=9
b
x+y+z=3
c
x+2y+3z=6
d
20x+23y+26z=69

detailed solution

Correct option is D

Equation of any plane through the line of intersection of the given planes is 2x+3y+4z+5+λ(x+y+z−6)=0It passes through( 1, 1, 1)if (2+3+4+5)+λ(1+1+1−6)=0⇒λ=14/3 and the required equation is therefore,20x+23y+26z=69.

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