The equation of the plane passing through the lines x−41=y−31=z−22  and x−31=y−2−4=z5

Here, the required plane is a (x - 4) + b (y- 3) + c (z -2) = 0 Also a+b+2c -0 and a-4b +5c-0 Solving, we havea5+8=b2−5=c−4−1=ka13=b−3=c−5=kTherefore, the required equation of plane is    -13x+3y+5z+33=0