The equation of the plane passing through the point (0, 1, -4) and normal to the line joining the points(0,–2, 2) and (–3, 1, –2) is ax + by + cz + d= 0 then
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a
a > b > c > d
b
d > c > a > b
c
a > c > d > b
d
c > d > b > a
answer is B.
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Detailed Solution
P(0,1,-4) dr's of AB→(-3 – 0,1 + 2, - 2 -2) (a,b,c) = (-3, 3, -4)Equation of the plane is -3 ( x – 0 ) +3( y – 1) – 4 (z + 4) = 0 - 3x + 3 y – 4z – 19 = 0 3x - 3y + 4z + 19 = 0 ax + by + cz + d = 0 d > c > a > b