The equation of the plane passing through the point (1, 2, - 3) and perpendicular to the planes 3x + y – 2z = 5 and 2x – 5y – z = 7, is :

Normal vector of required plane isn→=i^j^k^31−22−5−1=−11i^−j^−17k^Therefore, the equation of the plane is 11 (x – 1) + (y – 2) + 17 (z + 3) = 0, it implies 11x + y + 17z + 38 = 0