Equation of the plane passing through the points (2,2,1) and (9, 3, 6), and perpendicular to the plane 2x+6y+6z- 1=0 is
Any plane through (2,2, 1) is a(x-2)+b(y-2)+c(z- 1)=0 -------(i)
It passes through (9, 3, 6) if 7a+ b + 5c=0 --------(ii)
Also (i) is perpendicular to 2x + 6y + 6z - 1 = 0,
we have
Therefore, the required plane is 3(x - 2) + 4 (y - 2) - 5 (z- 1) = 0 or 3x + 4y - 5z -9 = 0