Q.

The equation of the plane through the intersection of the planes x+2y+3z-4=0 and  4x+3y+22+ 1 = 0 and passing through the origin is

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a

17x+14y+11z=0

b

7x+4y+z=0

c

x+14y+11z=0

d

17x+y+z=0

answer is A.

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Detailed Solution

Any plane through the given planes is  x+2y+3z−4+λ(4x+3y+2z+1)=0It passes through (0, 0, 0). Therefore, -4+λ=0                                                    or, λ=4Therefore, the required plane is x + 2y + 3z + 4(4x + 3y + 2z) = 0 or 17x + 14y + 11z=0.
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