Equation of the plane through the lines x−12=y+1−2=z−31 andx−11=y+12=z−32  is

The Equation of the plane through the lines x−12=y+1−2=z−31 andx−11=y+12=z−32  is x−x1y−y1z−z1l1m1n1l2m2n2=0Hence the equation of the plane required is x−1y+1z−32−21122=0Simplify   x−1−4−2−y+13+z−36=02x−1+y+1−2z−3=02x+y−2z+5=0          Therefore, the equation of the required plane is 2x+y−2z+5=0