Equation of the plane through the mid-point of the join of A(4,5,-10) and B(-1,2,1) and perpendicular to AB is

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5x+3y−11z+1352=0

5x+3y−11z=1352

5x+3y+11z=135

5x+3y−11z+1852=0

answer is B.

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Detailed Solution

Mid point of AB = 32,72,−92D.r’s of AB are (5,3,-11)Equation of plane is r¯−(32i¯+72j¯−92k¯).(5i¯+3j¯−11k¯)=0 r¯.(5i¯+3j¯−11k¯)=1352

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