Questions

The equation of the plane which is at a distance $3\sqrt{3}$ units from origin and the normal to which is equally inclined to coordinate axes is

a

x+y+z=9

b

x+y-z=9

c

x+y+z=3

d

x+y+z=0

detailed solution

Correct option is A

Dc's of normal (l,m,n)=13,13,13P=3Equation of plane lx+my+nz=P

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The equation of a plane which passes through the point of intersection of lines $\frac{x-1}{3}=\frac{y-2}{1}=\frac{z-3}{2}$ and $\frac{x-3}{1}=\frac{y-1}{2}=\frac{z-2}{3}$ and at greatest distance from point (0,0,0) is

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