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The equation of a plane which passes through the point of intersection of lines $\frac{x - 1}{3} = \frac{y - 2}{1} = \frac{z - 3}{2}$ and $\frac{x - 3}{1} = \frac{y - 1}{2} = \frac{z - 2}{3}$ and at greatest distance from point (0,0,0) is

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4x+3y+5z=25

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Correct option is B

Let a point (3λ+1,λ+2,2λ+3) of the first line also lies on the second line Then 3λ+1−31=λ+2−12=2λ+3−23⇒λ=1Hence, the point of intersection P of the two lines is (4,3,5)verify options and perpendicular distance from origin is maximum

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The equation of a plane which passes through the point of intersection of lines x−13=y−21=z−32 and x−31=y−12=z−23 and at greatest distance from point (0,0,0) is

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The equation of a plane which passes through the point of intersection of lines $\frac{x - 1}{3} = \frac{y - 2}{1} = \frac{z - 3}{2}$ and $\frac{x - 3}{1} = \frac{y - 1}{2} = \frac{z - 2}{3}$ and at greatest distance from point (0,0,0) is