Questions
The equation of the plane which passes through the z-axis and is perpendIcular to the line is
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a
x+ytanθ=0
b
y+xtanθ=0
c
xcosθ−ysinθ=0
d
xsinθ−ycosθ=0
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Correct option is A
The d.r’s of the normal of the plane are (cosθ,sinθ, 0).Now, the required plane passes through the z-axis. hence the point (0,0,0) lies on the plane.The required plane is xcosθ+ysinθ=0, ⇒x+ytanθ=0
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The vector equation of the line passing through (1,2,3) and parallel to the planes and is
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