Q.
The equation of the plane which passes through the z-axis and is perpendIcular to the line x−acosθ=y+2sinθ=z−30 is
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
a
x+ytanθ=0
b
y+xtanθ=0
c
xcosθ−ysinθ=0
d
xsinθ−ycosθ=0
answer is A.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
The d.r’s of the normal of the plane are (cosθ,sinθ, 0).Now, the required plane passes through the z-axis. hence the point (0,0,0) lies on the plane.The required plane is xcosθ+ysinθ=0, ⇒x+ytanθ=0
Watch 3-min video & get full concept clarity