Q.
Equation of the rectangular hyperbola whose focus is (1,-1) and the corresponding directrix is x - y + 1 = 0 is
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a
x2−y2=1
b
xy = 1
c
2xy - 4x + 4y + 1 =0
d
2xy + 4x - 4y - 1 = 0
answer is C.
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Detailed Solution
Eccentricity of rectangular hyperbola is 2∴ Equation of hyperbola is (x−1)2+(y+1)2=2|x−y+1|12+(−1)2or (x−1)2+(y+1)2=(x−y+1)2or 2xy−4x+4y+1=0
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