The equation asinx+bcosx=c , where c>a2+b2 has
a unique solution
infinite number of solutions
no solution
none of these
Let a=rcosα, b=rsinα so that r=a2+b2
The given equation can be written as rsinx+α=c⇒sinx+α=ca2+b2
⇒sinx+α=ca2+b2>1 is not possible as sinx always≤1
hence c>a2+b2 is not possible for any value of x