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a
a unique solution
b
infinite number of solutions
c
no solution
d
none of these
answer is C.
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Detailed Solution
Let a=rcosα, b=rsinα so that r=a2+b2The given equation can be written as rsinx+α=c⇒sinx+α=ca2+b2⇒sinx+α=ca2+b2>1 is not possible as sinx always≤1 hence c>a2+b2 is not possible for any value of x