Questions
The equation is solvable for
a
−52≤α≤12
b
−3≤α≤1
c
−32≤α≤12
d
−1≤α≤1
detailed solution
Correct option is C
We have sin2x+cos2x2−2sin2xcos2x+sin2x+α=01-sin22x2+sin2x+α=0⇒sin22x−2sin2x−2−2 α=0⇒sin2x=2±4-4(-2-2α)2 ⇒sin2x=1±3+2α⇒-1≤sin2x≤1 ⇒-1≤1±3+2α ≤1⇒ -2≤±3+2α≤0 negecting positive sign-2≤-3+2 α≤04≥3+2α≥0−32≤α≤12Talk to our academic expert!
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