The equation of the smallest circle passing through the points of intersection of the line x+y−1=0 and the circle x2+y2=9
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a
x2+y2+x+y−8=0
b
x2+y2−x−y−8=0
c
x2+y2−x+y−8=0
d
x2+y2−x−y+8=0
answer is B.
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Detailed Solution
Given circle x2+y2=9.......(1) and line if x+y−1=0............(2) The point of intersection of (1)&(2) is (1)+λ(2)=0 ⇒x2+y2−9+λ(x+y−1)=0 ⇒x2+y2+λx+λy−λ−9=0.........(3) Centre (−λ2,−λ2) Since equation (3) is a smallest circle then equation (2) is a diameter of the circle⇒Centre(−λ2,−λ2) lies on (2) −λ2,−λ2−1=0⇒λ=−1 Substituting λ=−1 in equation (3) ⇒x2+y2−9−(x+y−1)=0 ⇒x2+y2−x−y−8=0