The equation of straight line passing through (−a,0) and making the triangle with axes of area T is

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2Tx+a2y+2aT=0

2Tx−a2y+2aT=0

2Tx−a2y−2aT=0

2Tx+a2y−2aT=0

answer is B.

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Detailed Solution

If the line cuts off the axes at A and B, then area of triangle is 12×a×OB=T⇒OB=2Ta Hence, the equation of line is x−a+y2T/a=1 2Tx−a2y+2aT=0

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