The equation of straight line passing through (−a,0) and making the triangle with axes of area T is
2Tx+a2y+2aT=0
2Tx−a2y+2aT=0
2Tx−a2y−2aT=0
2Tx+a2y−2aT=0
If the line cuts off the axes at A and B, then area of triangle is 12×a×OB=T⇒OB=2Ta
Hence, the equation of line is x−a+y2T/a=1