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The equation of straight line passing through (a,0) and making the triangle with axes of area T is

a
2Tx+a2y+2aT=0
b
2Tx−a2y+2aT=0
c
2Tx−a2y−2aT=0
d
2Tx+a2y−2aT=0

detailed solution

Correct option is B

If the line cuts off the axes at A and B, then area of triangle is 12×a×OB=T⇒OB=2Ta Hence, the equation of line is  x−a+y2T/a=1   2Tx−a2y+2aT=0

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