The equation of straight line passing through (-a, 0) and making a triangle with the axes of area T is

If the line cuts off the axes at A and B, then the area of triangle is 12×OA×OB=T or  12×a×OB=T or  OB=2TaHence, the equation of line is  x−a+y2T/a=1 or  2Tx−a2y+2aT=0