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Questions  

 The equation of straight line passing through (-a, 0) and making a triangle with the axes of area T is

a
2Tx+a2y+2aT=0
b
2Tx−a2y+2aT=0
c
2Tx−a2y−2aT=0
d
None of these

detailed solution

Correct option is B

If the line cuts off the axes at A and B, then the area of triangle is 12×OA×OB=T or  12×a×OB=T or  OB=2TaHence, the equation of line is  x−a+y2T/a=1 or  2Tx−a2y+2aT=0

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