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Questions  

The equation of the straight line which passes through the point4,3 such that the portion of the line between the axes is divided internally by the point in the ratio 5:3 is 

a
9x−20y+96=0
b
9x+20y=24
c
20x+9y+53=0
d
None of these

detailed solution

Correct option is A

Let the cuts the axes at points Aa,0 and B0,b. Now, given that −4,3 divides AB in the ratio 5:3. Then, −4=3a/8 and 3=5b/8. Therefore a=−32/3 and b=24/5. Then using the intercept form x/a+y/b=1, the equation of line is −3x32+5y24=1or 9x−20y+96=0

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