The equation of the straight line which passes through the point−4,3 such that the portion of the line between the axes is divided internally by the point in the ratio 5:3 is

Let the cuts the axes at points Aa,0 and B0,b. Now, given that −4,3 divides AB in the ratio 5:3. Then, −4=3a/8 and 3=5b/8. Therefore a=−32/3 and b=24/5. Then using the intercept form x/a+y/b=1, the equation of line is −3x32+5y24=1or 9x−20y+96=0