Questions
The equation of the straight line which passes through the point (-4, 3) such that the portion of the line between the axes is divided internally by the point in the ratio 5:3is
a
9x−20y+96=0
b
9x+20y=24
c
20x+9y+53=0
d
None of these
detailed solution
Correct option is A
Let the line cuts the axes at points A(a, 0) and B(0, b). Now, given that (−4,3) divides AB in the ratio 5:3 . Then, −4=3a/8 and 3=5b/8 . Therefore, a=−32/3 and b=24/5 . Then using the intercept form xa+yb=1 , the equation of line is −3x32+5y24=1 or 9x−20y+96=0Talk to our academic expert!
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