Q.

The equation of the straight line which passes through the point (-4, 3) such that the portion of the line between the axes is divided internally by the point in the ratio 5:3is

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a

9x−20y+96=0

b

9x+20y=24

c

20x+9y+53=0

d

None of these

answer is A.

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Detailed Solution

Let the line cuts the axes at points A(a, 0) and B(0, b). Now,  given that (−4,3) divides AB in the ratio 5:3 . Then, −4=3a/8 and 3=5b/8 . Therefore, a=−32/3 and b=24/5 . Then using  the intercept form xa+yb=1 , the equation of line is  −3x32+5y24=1 or 9x−20y+96=0
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