The equation of the tangent to the circle x2+y2=25 passing through (-2, 11) is

The equation of any tangent to the circle x2+y2=25 is of the form  y=mx+51+m2         (where m is the slope)  It passes through (−2,11). Therefore,  11=−2m+51+m2  or  (11+2m)2=251+m2  or  m=247,−43 Therefore, the equation of tangent is 24x−7y+125=0 or 4x+3y=25