The equation of the tangent to the curvey=∫x2x3 dt1+t2 at x=1 is

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2y+1=x

3x+1=y

3x+1+3=y

none of these

answer is D.

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Detailed Solution

dydx=11+t2t=x3ddxx3−11+t2t=x2ddxx2=3x21+x6−2x1+x4dydxx=1=12Also y(1)=0.So the equation of tangent is y−0=12(x−1)

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