Equation of a tangent to the ellipse x236+y225=1passing through the point where a directrix of the ellipse meets the positive x-axis is
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a
5y+11x=36
b
6y+11x=25
c
6y+11x=36
d
5y−11x=36
answer is C.
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Detailed Solution
Equation of a tangent to the ellipse is y=mx+36m2+25 (1)Equation of the directrix is x=6×636−25=3611 which meets the +ve x axis at 3611,0The tangent ( 1) passes through this point if m36112=36m2+25⇒m2=1136⇒m=116.Since the tangent meets the directrix on positive a-axis m<0 and the required equation is y=−116x+36×1136+256y+11x=36