Q.

The equation of the transverse axis of the hyperbola (x−3)2+(y+1)2=(4x+3y)2  is

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a

x + 3y = 0

b

4x + 3y = 9

c

3x – 4y = 13

d

4x + 3y = 0

answer is C.

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Detailed Solution

Transverse Axis is perpendicular 4x+3y=0  and passing through (3, -1) is 3x - 4y=13
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