Q.
The equation of the transverse axis of the hyperbola (x−3)2+(y+1)2=(4x+3y)2 is
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a
x + 3y = 0
b
4x + 3y = 9
c
3x – 4y = 13
d
4x + 3y = 0
answer is C.
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Detailed Solution
Transverse Axis is perpendicular 4x+3y=0 and passing through (3, -1) is 3x - 4y=13
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