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Q.

The equation whose roots are cubes of the roots x3+2x2+3=0  is

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a

x3+6x2−36x+27=0

b

x3−5x3−11x+3=0

c

x3−23x2+13x−36=0

d

x3+17x2+27x+27=0

answer is D.

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Detailed Solution

f(y3)=0 y+2y23+3=0 (y+3)3=−8y2 ⇒y3+17y2+27y+27=0
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The equation whose roots are cubes of the roots x3+2x2+3=0  is