The equation whose roots are the square of the roots of the equation 2x2+3x+1=0

Let the roots of equation2x2+3x+1=0 is α and βThen ,α+β=−32 and αβ=12∴ α2+β2=(α+β)2−2αβ=−322−2×12=94−1=54and α2β2=122=14∴ Required equation isx2−α2+β2x+α2β2=0⇒ x2−54x+14=0⇒ 4x2−5x+1=0