For the equation  3x2+px+3=0,p>0 If one of  the roots is square of the other, then  p is equal to

Let α and  α2 be the roots of the given equation. Then, α+α2=−p/3  and  α3=1 Now,  α3=1⇒α=1,ω,ω2Thus, the roots of the given equation are ω and  ω2 Therefore α=0 Now, ∴ α+α2=−p3⇒ω+ω2=−p3⇒−1=−p3⇒p=3