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The equation Δ=xaxbxcxbxcxaxcxaxb=0 is satisfied when 

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a
x=13(a+b+c)
b
x=12(a+b+c)
c
x=a+b+c
d
x=0

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detailed solution

Correct option is A

Using C1→C1+C2+C3, we get Δ=3x−(a+b+c)    x−b    x−c3x−(a+b+c)    x−c    x−a3x−(a+b+c)    x−a    x−bNote that ∆ becomes 0 when x=13(a+b+c).


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