Questions
For the equation
a
Exactly one value of xexists
b
Exactly two values of xexists
c
y=−1+nπ+π4,n∈z
d
y=1+nπ+π4,n∈z
detailed solution
Correct option is D
1−2x−x2=tan2x+y+cot2x+y⇒1−2x−x2-2=tan2x+y+cot2x+y-2⇒−x+12=tanx+y−cotx+y2Now L.Η.S≤0 and R.Η.δ≥0⇒−x+12=tanx+y−cotx+y2=0⇒ x=−1 and tanx+y=cotx+y ⇒ x=−1 and tan2−1+y=1 ⇒ x=−1 and −1+y=nπ±π4:n∈z⇒y=1+nπ±π4Talk to our academic expert!
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Number of values of and satisfying is
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