The equation a2−a−2x2+a2−4x+a2−3a+2=0 will have more than two solutions if a equal to

Given , a2−a−2x2+a2−4x+a2−3a+2=0-----iSince, Eq.(i) have more than two solutions.So, it is an Identity.∴a2−a−2=a2−4=a2−3a+2=0∵ if ax2+bx+c=0 is an identity, then a=b=c=0 a2−a−2=0⇒a=2,-1and a2-4=0⇒a=±2,and a2-3a+2=0⇒a=1,2therefore common value of a=2