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Theory of equations
Question

The equation xx+12+xx12=a(a1) has

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Solution

xx+12+xx12=a(a1) or  xx+1+xx122xx+1xx1=a(a1) or  2x2x2122x2x21a(a1)=0 or  t2ta(a1)=0  where t=2x2x21 t=a or 1a 2x2x21=a or 2x2x21=1a x=±aa2 or x=±a1a+1

When a<1all roots are real

1<a<2x=±a2ai,±a1a+1

 two real roots

When a>2all roots are real

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