The equation 1xx2x21xxx21=0 has,
exactly two distinct roots
one pair of equation real roots
three pairs of equal roots
Modulus of each root is 2
R1→R1+R2+R3 and take 1+x+x2 as common Δ=1+x+x211 1x21xxx21=1−x32
Therefore, Δ=0, has roots 1, 1, ω, ω, ω2, ω2.