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a
which are collinear
b
which lie on a circle with centre at (0, 0)
c
which lie on a circle with centre at (a, b)
d
none of these
answer is B.
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Detailed Solution
We havex2−a22+y2−b22=0⇒ x2−a2=0 and y2−b2=0⇒x=±a and y=±b.Thus, the points are (a, b), (a, -b), (- a, b) and (- a, -b).Clearly, these points lie on a circle x2+y2=a2+b2 having centre at the origin.