Questions
a
the length of whose transverse axis is 43
b
the length of whose conjugate axis is 4
c
whose center is (−1,2)
d
whose eccentricity is 19/3
detailed solution
Correct option is C
Let the equation of any normal be y=−tx+2t+t3. Since it passes through the point (15,12), we have 12=−15t+2t+t3 or t3−13t−12=0 One root is −1. Then, (t+1)t2+t−12=0 or t=1,3,4 Therefore, the co-normal points are (1,−2),(9,−6), and (16,8). Therefore, the centroid is (26/3,0).Talk to our academic expert!
Similar Questions
Let P(6,3) be a point on the hyperbola If the normal at the point P intersects the x-axis at (9, 0), then the eccentricity of the hyperbola is
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