The equations of the circles which touch both theaxes and the line x=a are
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a
x2+y2±ax±ay+a24=0
b
x2+y2+ax±ay+a24=0
c
x2+y2−ax±ay+a24=0
d
none of these
answer is C.
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Detailed Solution
Since the circle touches both the axes and the linex =a. Therefore, coordinates of its centre are (a/2,±a/2) and radius a/2. Hence, the required circles arex−a22+y∓a22=a22⇒x2+y2−ax±ay+a24=0