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Questions  

Equations of the common tangents of the circles x2+y 2 2x 6y+9=0 and x2 + y2 + 6x  2y + 1 = 0 are

A) x = 0   B) y = 4   C) 3x +4 y =10

a
A and B
b
B and C
c
A and C
d
A, B and C

detailed solution

Correct option is D

Equations of the given circles can be written as C1: (x – 1)2 + (y –3)2 = 1 having centre at (1, 3) and radius 1 and C2: (x + 3)2 + (y –1)2 = 9 having centre at (–3, 1) and radius 3.Both the circles clearly touch x = 0 and y = 4 Now        3×1+4×3−1032+42=1and         3(−3)+4(1)−1032+42=3Shows that both the circles touch 3x + 4y = 10 also.

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