First slide

Equation of line in Straight lines

Question

The equations of the diagonals of square formed by lines x =0 , y = 0, x = 1 and y = 1 are

Easy

A

$y = x, y + x = 1$
B

$y = x, x + y = 2$
C

$2 y = x, y + x = 1 / 3$
D

$y = 2 x, y + 2 x = 1$

Solution

The coordinates of the vertices of the square are A(0, 0), B(0, 1), C(1, 1), and D(1, 0).

Now, the equation of AC is y = x and that of BD is
$\begin{aligned} y - 1 = - \frac{1}{1} (x - 0) \\ or x + y = 1 \end{aligned}$

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