The equations of lines are given by sinθx+a=1+cosθy, sinθx−a=−1−cosθy. The locus of point of intersection of lines is xm+yn=al then l+m+n is
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answer is 3.
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Detailed Solution
Locus of point of intersection of two lines having parameter θ , is the equation obtained by eliminating θ from both equations x+ay=1+cosθsinθ And x−ay=−1−cosθsinθ Multiply both equationsx+ay⋅x−ay=−1+cosθsinθ⋅1−cosθsinθx2−a2y2=−1−cos2θsin2θ=−1x2−a2=−y2x2+y2=a2Here l=m=n=2 , Therefore, l+m+n=6