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The equations to a pair of opposite sides o fa parallelogram $are x^{2} - 5 x + 6 = 0 {and y}^{2} - 6 y + 5 = 0 . The equations to$ $its diagonals are$

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x+4y=13,y=4x−7

4x+y=13,4y=x−7

4x+y=13,y=4x−7

y−4x=13,y+4x=7

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Correct option is C

The sides of parallelogram are x=2,x=3,y=1,y=5The equation of diagonal AC is y−15−1=x−23−2 or y=4x−7and the equation of diagonal BD isx−23−2=y−51−5 or 4x+y=13

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The equations to a pair of opposite sides o fa parallelogram are x2−5x+6=0 and y2−6y+5=0 . The equations to its diagonals are

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The equations to a pair of opposite sides o fa parallelogram $are x^{2} - 5 x + 6 = 0 {and y}^{2} - 6 y + 5 = 0 . The equations to$ $its diagonals are$