The equations to a pair of opposite sides o fa parallelogram are x2−5x+6=0 and y2−6y+5=0 . The equations to its diagonals are
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a
x+4y=13,y=4x−7
b
4x+y=13,4y=x−7
c
4x+y=13,y=4x−7
d
y−4x=13,y+4x=7
answer is C.
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Detailed Solution
The sides of parallelogram are x=2,x=3,y=1,y=5The equation of diagonal AC is y−15−1=x−23−2 or y=4x−7and the equation of diagonal BD isx−23−2=y−51−5 or 4x+y=13