Questions
The equations to a pair of opposite sides of a parallelogram are and . The equations to its diagonals, are
a
x+4y=13 and y=4x−7
b
4x+y=13 and 4y=x−7
c
4x+y=13 and y=4x−7
d
y−4x=13 and y+4x=7
detailed solution
Correct option is C
Solving the equations of the sides taken in pairs, we obtain that the coordinates of the vertices A, B, C, D of theparallelogram ABCD are A (2, 1), B ( 3, 1), C ( 3, 5), D (2, 5)respectively. Hence, the equations of diagonals AC and BD are4x−y−7=0 and 4x+y−13=0.Talk to our academic expert!
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