First slide

Equation of line in Straight lines

Question

The equations of the pairs of opposite sides of a rectangle are $x^{2} - 7 x + 6 = 0 and y^{2} - 14 y + 40 = 0$ the equation of the diagonal nearer the origin is

Moderate

A

$5 x - 6 y + 14 = 0$
B

$6 x - 5 y + 14 = 0$
C

$6 x + 5 y - 56 = 0$
D

$6 x + 5 y - 14 = 0$

Solution

Vertices of the rectangle are $A (1, 4) B (6, 4), C (6, 10)$ and D(1, 10)
Equation of $A C$ is $6 x - 5 y + 14 = 0$
Equation of $B D$ is $6 x + 5 y - 56 = 0$
$A C$ is nearer the origin.

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