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The equations of the sides of a parallelogram are $x = 2, x = 3$ and $y = 1, y = 5$ .Equations to the pair of diagonals are

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4x+y=7,4x−y=13

x+4y=13,x−4y=7

x+4y=7,x−4y=13

4x+y=13,4x−y=7

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detailed solution

Correct option is D

The vertices of the parallelogram are A(2,1),B(2,5),C(3,5) and D(3,1) Equation of the diagonal AC isy−1=5−13−2(x−2)⇒4x−y=7Equation of the diagonal BD is y−5=1−53−2(x−2)⇒4x+y=13

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The equations of the sides of a parallelogram are x=2,x=3 and y=1,y=5 .Equations to the pair of diagonals are

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Ready to Test Your Skills?

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The equations of the sides of a parallelogram are $x = 2, x = 3$ and $y = 1, y = 5$ .Equations to the pair of diagonals are