Q.
The equations of the sides of a parallelogram are x=2,x=3 and y=1,y=5 .Equations to the pair of diagonals are
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a
4x+y=7,4x−y=13
b
x+4y=13,x−4y=7
c
x+4y=7,x−4y=13
d
4x+y=13,4x−y=7
answer is D.
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Detailed Solution
The vertices of the parallelogram are A(2,1),B(2,5),C(3,5) and D(3,1) Equation of the diagonal AC isy−1=5−13−2(x−2)⇒4x−y=7Equation of the diagonal BD is y−5=1−53−2(x−2)⇒4x+y=13
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