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Q.

Equations to the sides of a triangle are  x – 3y = 0, 4x + 3y = 5  and  3x + y = 0 The line 3x – 4y = 0 passes through the

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a

incentre

b

centroid

c

circumcentre

d

orthocentre of the triangle

answer is D.

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Detailed Solution

Sides x – 3y = 0 and 3x + y = 0 of the triangle being perpendicular to each other, the triangle is right angled at the origin, the point of intersection of these sides. So that origin is the orthocentre of the triangle and the line 3x – 4y = 0 passes through this orthocentre
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