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Questions  

Equations to the sides of a triangle are  x  3y = 0, 4x + 3y = 5  and  3x + y = 0 The line 3x  4y = 0 passes through the 

a
incentre
b
centroid
c
circumcentre
d
orthocentre of the triangle

detailed solution

Correct option is D

Sides x – 3y = 0 and 3x + y = 0 of the triangle being perpendicular to each other, the triangle is right angled at the origin, the point of intersection of these sides. So that origin is the orthocentre of the triangle and the line 3x – 4y = 0 passes through this orthocentre

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