The equations of the tangents drawn from the origin to the circle x2+y2−2rx−2hy+h2=0 , is
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a
x=0,y=0
b
y=0,h2−r2x−2rhy=0
c
x=0,h2−r2x−2 rhy =0
d
x=0,h2−r2x+2rhy=0
answer is C.
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Detailed Solution
The combined equation of the pair of tangents drawn from (x1, y1) to a circle S=0 is given by SS'=T 2 .So, the equations of the tangents drawn from (0, 0) to x2+y2−2rx−2hy+h2=0a are given by h2x2+y2−2rx−2hy+h2=−xr−hy+h22⇒xh2−r2x−2rhy=0⇒x=0 or h2−r2x−2 rhy =0