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Q.

The equations of the tangents drawn from the origin to the circle x2+y2−2rx−2hy+h2=0 , is

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a

x=0,y=0

b

y=0,h2−r2x−2rhy=0

c

x=0,h2−r2x−2 rhy =0

d

x=0,h2−r2x+2rhy=0

answer is C.

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Detailed Solution

The combined equation of the pair of tangents drawn from  (x1, y1) to a circle S=0 is given by SS'=T 2 .So, the equations of the tangents drawn from (0, 0) to    x2+y2−2rx−2hy+h2=0a are given by h2x2+y2−2rx−2hy+h2=−xr−hy+h22⇒xh2−r2x−2rhy=0⇒x=0 or h2−r2x−2 rhy =0
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