Q.

The equations of two altitudes of an equilateral triangle are 3x−y+8−43=0 and 3x+y−12−43=0. The equation of the third altitude is

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a

3x+y=4

b

y=10

c

x=10

d

x−3y=4

answer is B.

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Detailed Solution

Solve the given equations and verify with the options.
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