Q.
The equations of two altitudes of an equilateral triangle are 3x−y+8−43=0 and 3x+y−12−43=0. The equation of the third altitude is
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a
3x+y=4
b
y=10
c
x=10
d
x−3y=4
answer is B.
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Detailed Solution
Solve the given equations and verify with the options.
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