The equations a2x2+2h(a+b)xy+b2y2=0 and ax2+2hxy+by2=0
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
two pairs of perpendicular straight lines
b
two pairs of parallel straight lines
c
two pairs of straight lines which are equally inclined to each other
d
None of these
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
The given equations are a2x2+2h(a+b)xy+b2y2=0______(1)and ax2+2hxy+by2=0_____(2)The equation of the bisectors of the angles between the lines represented by (1) is x2−y2a2−b2=xyh(a+b)or x2−y2a−b=xyh which is the same as the equation of bisectors of the angles between the line pair (2). Thus, two line pairs are equally inclined to each other.